A 1kg ninja star is hung from the end of a vertical spring with a spring constant of 20 N/m. When the ninja star comes to rest, how far will the spring have stretched?
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Correct Answer: B. 0.5 m.
Once the ninja star comes to rest at the end of the spring, the upward force by the spring must balance the downward force of gravity. That is, kx = mg. Solving for x yields x = mg/k (1)(10)/(20) = 0.5 m.
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