A MCAT book weighing 40 N is held in contact with the ceiling of a room by an upward force of 50 N. What is the magnitude of the normal force exerted by the ceiling on the book?
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Correct Answer: B. 10 N
What are the forces on the book? The weight, 40 N, and the normal force, N are downward forces, and the only upward force is our 50 N push. Since the bloc k is not accelerating vertically, the net vertical force must be zero. Therefore, 40 + N must be 50, which means N = 10 N.
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