A construction worker uses a crane to vertically lift an object weighing 2000 N to the top of a platform at a constant rate. If it takes 30 seconds to lift the object 150 meters, what is the rate of energy consumed by the motor in the crane?

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Correct Answer: **C.** *10 kW.*

We can use the equation Power = Force*velocity to solve this problem. The object moves 150 meters in 30 seconds, so the velocity must be (150m/30s) = 5 m/s. Plugging this back into the original equation of P = Fv, then P = (2000 N)(5 m/s) = 10 kW.

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