Radiation therapy uses high energy photons to ionize the DNA in malignant cells. If UVB light has enough energy to create pyrimidine dimers, what part of the electromagnetic spectrum can be used for its curative, higher energy effects.
I.) X-rays and gamma rays.
II.) Radio waves and micro waves.
III.) NIR and Green light.
Loading ...
Correct Answer: A. I only
We are looking for something with more energy than UVB radiation. We 1st need to know where UVB radiation lies on the electromagnetic spectrum. Recall that UVB is ultra violet, meaning that it exists just beyond the visible color violet.
What helps me remember the EM spectrum is the last word of each part. We have UV rays and IR waves. The rays are grouped together on one side of visible light, and the waves are grouped together on the other side. Now that we have an order we need a direction. Rays are more energetic than visible light. You can think about how long it takes for an ocean wave to pass and how quickly a sunray can hit you. This leaves only X-rays and gamma rays to having more energy than UVB.
Get it right? Tweet at us:
Subscribe below to receive the MCAT Question of the Day delivered straight to your inbox every morning.
Photo attributed to ScientificRelevance.
