2 Ag2O -> 4 Ag + O2
A chemist runs the above reaction and produces one mole of Ag. How many grams of oxygen gas are produced?
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Correct Answer: C. 8 grams.
From the balanced equation, we can see that 4 moles of Ag are produced for every 1 mole of O2. Therefore, if 1 mole of Ag is produced, then (1/4) mole of O2 is produced. The mass of (1/4) mole of O2 is (1/4)(2)(16 g/mol) = 8 grams.
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