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Three identical 12 ohm resistors are connected in parallel to a 8V battery. What is the total power dissipated in the circuit?
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Correct Answer: C. 16 W
When resistors are in parallel, we can find equivalent resistance simply by using the equation:
(1/Req) = (1/R1) + (1/R2) + … + (1/Rn)
In this case, the equivalent resistance is: (1/Req) = (1/12)+(1/12)+(1/12)= 3/12
We find that Req = 4. We then input this into our equation for the power of a circuit
P = IV = V2/R = 82/4= 16W
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